Rank row without analytical functions









SQL>

SQL>

SQL> – create demo table

SQL> create table Employee(

  2    ID                 VARCHAR2(BYTE)         NOT NULL,

  3    First_Name         VARCHAR2(10 BYTE),

  4    Last_Name          VARCHAR2(10 BYTE),

  5    Start_Date         DATE,

  6    End_Date           DATE,

  7    Salary             Number(8,2),

  8    City               VARCHAR2(10 BYTE),

  9    Description        VARCHAR2(15 BYTE)

 10  )

 11  /



Table created.



SQL>

SQL> – prepare data

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)

  2               values (‘01‘,’Jason‘,    ’Martin‘,  to_date(‘19960725‘,’YYYYMMDD‘), to_date(‘20060725‘,’YYYYMMDD‘), 1234.56‘Toronto‘,  ’Programmer‘)

  3  /



row created.



SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)

  2                values(‘02‘,’Alison‘,   ’Mathews‘, to_date(‘19760321‘,’YYYYMMDD‘), to_date(‘19860221‘,’YYYYMMDD‘), 2334.78‘Vancouver‘,’Tester‘)

  3  /



row created.



SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)

  2                values(‘03‘,’James‘,    ’Smith‘,   to_date(‘19781212‘,’YYYYMMDD‘), to_date(‘19900315‘,’YYYYMMDD‘), 2334.78‘Vancouver‘,’Tester‘)

  3  /



row created.



SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)

  2                values(‘04‘,’Celia‘,    ’Rice‘,    to_date(‘19821024‘,’YYYYMMDD‘), to_date(‘19990421‘,’YYYYMMDD‘), 2334.78‘Vancouver‘,’Manager‘)

  3  /



row created.



SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)

  2                values(‘05‘,’Robert‘,   ’Black‘,   to_date(‘19840115‘,’YYYYMMDD‘), to_date(‘19980808‘,’YYYYMMDD‘), 2334.78‘Vancouver‘,’Tester‘)

  3  /



row created.



SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)

  2                values(‘06‘,’Linda‘,    ’Green‘,   to_date(‘19870730‘,’YYYYMMDD‘), to_date(‘19960104‘,’YYYYMMDD‘), 2334.78,‘New York‘,  ’Tester‘)

  3  /



row created.



SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)

  2                values(‘07‘,’David‘,    ’Larry‘,   to_date(‘19901231‘,’YYYYMMDD‘), to_date(‘19980212‘,’YYYYMMDD‘), 2334.78,‘New York‘,  ’Manager‘)

  3  /



row created.



SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)

  2                values(‘08‘,’James‘,    ’Cat‘,     to_date(‘19960917‘,’YYYYMMDD‘), to_date(‘20020415‘,’YYYYMMDD‘), 2334.78,‘Vancouver‘, ’Tester‘)

  3  /



row created.



SQL>

SQL>

SQL>

SQL> – display data in the table

SQL> select from Employee

  2  /



ID   FIRST_NAME LAST_NAME  START_DAT END_DATE      SALARY CITY       DESCRIPTION

—- ———- ———- ——— ——— ———- ———- —————

01   Jason      Martin     25-JUL-96 25-JUL-06    1234.56 Toronto    Programmer

02   Alison     Mathews    21-MAR-76 21-FEB-86    2334.78 Vancouver  Tester

03   James      Smith      12-DEC-78 15-MAR-90    2334.78 Vancouver  Tester

04   Celia      Rice       24-OCT-82 21-APR-99    2334.78 Vancouver  Manager

05   Robert     Black      15-JAN-84 08-AUG-98    2334.78 Vancouver  Tester

06   Linda      Green      30-JUL-87 04-JAN-96    2334.78 New York   Tester

07   David      Larry      31-DEC-90 12-FEB-98    2334.78 New York   Manager

08   James      Cat        17-SEP-96 15-APR-02    2334.78 Vancouver  Tester



rows selected.



SQL>

SQL>

SQL>

SQL> – without analytical functions:

SQL>

SQL> SELECT id, first_name, os Salary, ROWNUM Toprank

  2  FROM

  3    (SELECT id, first_name, salary os

  4    FROM employee

  5    ORDER BY salary desc)

  6  ORDER BY first_name;



ID   FIRST_NAME     SALARY    TOPRANK

—- ———- ———- ———-

02   Alison        2334.78          2

04   Celia         2334.78          1

07   David         2334.78          7

03   James         2334.78          3

08   James         2334.78          4

01   Jason         1234.56          8

06   Linda         2334.78          6

05   Robert        2334.78          5



rows selected.



SQL>

SQL>

SQL>

SQL> – clean the table

SQL> drop table Employee;



Table dropped.



SQL>

SQL>

SQL>

           

       

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